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Problem Description Let \(S\) be the set of positive integers \(N\) with the property that the last four digits of \(N\) are \(2020\), and when the last four digits are removed, the result is a divisor of \(N\). For example, \(42,020\) is in \(S\) because \(4\) is a divisor of \(42,020\). Find the sum of all the digits of all the numbers in \(S\). For example, the number \(42,020\) contributes \(4+2+0+2+0=8\) to this total.

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Solution 093

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